Welcome to distributive and the Amazing Math Maze. So, either you missed Question 12 of the aMazing Math Maze of you found this page doing a search for the distributive law. I would love to tell you about the aMazing Math Maze which was built for Algebra 1 students - but first I would like to talk about question 12. There are people doing really well with the Maze that have missed Question 12 and we are about to tell them why - and give them another shot at it.
If you'll recall the question looked like this -
3x(x4+ x - 3)
a) 3x4 + 4x – 3
b) 3x5 + x – 3c) 3x5 + 3x – 9
d) 3x5 + 3x2 - 9xAnd, I mentioned that we would be using the distributive property. By this I meant that we would multiply each term in the parentheses by the term outside the parentheses. So each item gets multiplied by 3x.
In answer A we multiplied the first term by 3 but not by x. It should have raised the exponent to 5.
In answer B we multiplied the first term by 3x but not the second or third.
In answer C we were correct in the first term, but failed to multiply the second or third term by the x.
Answer D was the correct answer.
In the above example I used arrows to show what the term outside the parenthesis gets multiplied times. 6x squared first gets multiplied times the 3x cubed, and we get 18 x to the fifth. 6 times 3 is 18 and x squared times x to the third is x to the 5th. The purple arrow shows the next multiplication resulting in negative 12 x to the fourth, then the brown arrow ends up being 24 x squared. Note that we leave the negative 2x alone - it' not in the parenthesis. And the whole mess equals 5. If you like worksheets (and who doesn't?) Kutra Software is a good resource. Keeping in mind, I am accepting no remuneration from them (mostly because it hasn't been offered). Anyway, if you have any comments about their service, I am very curious as to your experience. Please write me a note using the form at the bottom of this page - thanks.
2x2(x3+ 6) -7
a) 2x5 + 12x2 – 7
b) 3x5 + 12x – 7c) 2x5 + 12x2 – 14x2
d) 2x5 - 2x2
Click a letter corresponding to the most correct answer of the expression.