Mathematics Help Central and the aMAZEing Math Maze
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Welcome to Mathematics Help Central. This is also a landing page for those who had trouble answering Question 9 in the aMAZEing Maze. The amazing maze is a series of questions and help pages primarily aimed at Algebra 1 students. But believe me, some of the questions require a bit of thought. Anyway, I do want to offer Math Help and will do so at the end of this page. First I want to help anyone who had trouble answering question 9 of the maze - so here goes.
Question 9a - Working with Polynomials.
Well, gee. Missed it again. This one had a bit of a trick to it, so let me explain. The formula was ...
5x2 + 6x + 4 = 4x2 + 2xO'k, so the first thing to do is to get all the variables to one side. I do this by subtracting 4x squared from both sides. Notice, on the right side of the equation, 4x squared minus 4x squared equals 0. But I'm also subtracting 2x from both sides. I'm getting all my variables to one side.
5x2 -4x2 + 6x - 2x + 4 = 4x2 - 4x2 + 2x - 2xI did quite a bit there, I subtracted the 4x squared from both sides and the 2x from both sides. Now my formula looks like -
x2 + 4x + 4 = 0Remember, I can only combine like terms. We are now ready for Step 4 - factoring. I need to find two numbers that multiply together to equal 4 and add together to equal 4. 2 and 2 seems to fit the bill. 2x2 = 4 and 2 + 2 = 4. So, the factors of this equation are -
(x + 2)(x + 2) =0 Both of the factors are (x + 2), so we only have one root which means we can eliminate answers a and c. Looking at (x + 2) = 0 and solving for x, we need to subtract 2 from both sides and get (x = 2) - 2 = -2 or x = -2.
The answer is b, x = -2.
Mathematics Help Central
Well, there are a lot of great places to get help on the net. I like to think of this as one of them. Playing the aMAZEing Math Maze is a good way to get help with Algebra 1 or just to refresh your skills.ABCMouse
XIII. Linear Equations
XVII. Real Numbers
XIV. Math Terms
XVIII. Percentages